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Find the coefficient of x^2 in the product (x – 1) (x – 5) (x – 6). - Mathematics

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प्रश्न

Find the coefficient of x2 in the product (x – 1) (x – 5) (x – 6).

योग
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उत्तर

Given: Find the coefficient of x2 in the product (x – 1)(x – 5)(x – 6).

Step-wise calculation:

1. First multiply two factors:

(x – 1)(x – 5) = x2 – 5x – x + 5

(x – 1)(x – 5) = x2 – 6x + 5

2. Now multiply the result by the third factor (x – 6): 

(x2 – 6x + 5)(x – 6)

3. Expand this product:

= x2 × x – x2 × 6 – 6x × x + 6x × 6 + 5 × x – 5 × 6

= x3 – 6x2 – 6x2 + 36x + 5x – 30

4. Combine like terms:

= x3 – (6x2 + 6x2) + (36x + 5x) – 30

= x3 – 12x2 + 41x – 30

The coefficient of x2 in the expanded product (x – 1)(x – 5)(x – 6) is (–12).

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अध्याय 3: Expansions - Exercise 3A [पृष्ठ ६४]

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नूतन Mathematics [English] Class 9 ICSE
अध्याय 3 Expansions
Exercise 3A | Q 16. | पृष्ठ ६४
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