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प्रश्न
Find the area of sector bounded by the circle x2 + y2 = 25, in the first quadrant−
योग
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उत्तर
Given equation of the circle is x2 + y2 = 25
∴ y2 = 25 − x2
∴ y = `+- sqrt(25 - x^2)`
∴ y = `sqrt(25 - x^2)` .....[∵ In first quadrant, y > 0]
∴ Required area = `int_0^5 y "d"x`
= `int_0^5 sqrt(25 - x^2) "d"x`
= `[x/2 sqrt(25 - x^2) + 25/2 sin^-1 (x/5)]_0^5`
= `0 + 25/2 sin^-1 (1) - 0`
= `25/2 (pi/2)`
= `(25pi)/4` sq.units
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