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प्रश्न
Find the area of each of the following figure:
योग
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उत्तर
In right ΔQRP,
RP2 = PQ2 - QR2
= 152 - 92
= 225 - 81
= 144
⇒ RP = 12cm
Area of ΔQRP
= `(1)/(2) xx "QR" xx "RP"`
= `(1)/(2) xx 9 xx 12`
= 54cm2
∴ Area of given figure
= Area of ΔQRP + Area of ΔRPS
= 54cm2 + 108cm2
= 162cm2.
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