Advertisements
Advertisements
प्रश्न
Find the area of a triangle, whose sides are :
10 cm, 24 cm, and 26 cm
Advertisements
उत्तर
Sides of ∆ are
a = 10 cm
b = 24 cm
c = 26 cm
S = `(a + b + c)/2 = (10 + 24 + 26)/2`
= `60/2 = 30`
area of Δ = `sqrt(S(S - a)(S - b)(S - c))`
= `sqrt(30(30 - 10)(30 - 24)(30 - 26))`
= `sqrt(30 xx 20 xx 6 xx 4)`
= `sqrt(10 xx 3 xx 10 xx 2 xx 2 xx 3 xx 2 xx 2)`
= `sqrt(10 xx 10 xx 3 xx 3 xx 2 xx 2 xx 2 xx 2)`
= `10 xx 3 xx 2 xx 2 = 120 "cm"^2`
APPEARS IN
संबंधित प्रश्न
Find the area of an isosceles triangle with perimeter is 36 cm and the base is 16 cm.
The sides of a triangular field are in the ratio 5: 3: 4 and its perimeter is 180 m. Find:
- its area.
- the altitude of the triangle corresponding to its largest side.
- the cost of leveling the field at the rate of Rs. 10 per square meter.
Two sides of a triangle are 6.4 m and 4.8 m. If the height of the triangle corresponding to 4.8 m side is 6 m;
find :
(i) area of the triangle ;
(ii) height of the triangle corresponding to 6.4 m sides.
The base and the height of a triangle are in the ratio 5 : 3. If the area of the triangle is 67.5 m2; find its base and height.
A field is in the shape of a quadrilateral ABCD in which side AB = 18 m, side AD = 24 m, side BC = 40m, DC = 50 m and angle A = 90°. Find the area of the field.
One of the equal sides of an isosceles triangle is 13 cm and its perimeter is 50 cm. Find the area of the triangle.
Use the information given in the adjoining figure to find :
(i) the length of AC.
(ii) the area of an ∆ABC
(iii) the length of BD, correct to one decimal place.
Find the area of a triangle whose base is 3.8 cm and height is 2.8 cm.
Find the area of a triangle with a base 12cm and a height equal to the width of a rectangle having area of 96cm2 and a length of 12cm.
A piece of wire is 36 cm long. What will be the length of each side if we form an equilateral triangle
