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प्रश्न
Find the 4th vertex of a parallelogram if three vertices taken in order are (1, −1), (−2, 2), and (4, 8).
योग
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उत्तर
Here, let;
- A = (1, −1),
- B = (−2, 2),
- C = (4, 8)
For a parallelogram with vertices A, B, C, D taken in order, the fourth vertex is D = A + C − B,
Computing:
⇒ Dx = A + C − B
= 1 + 4 − (−2)
∴ Dx = 7
⇒ Dy = A + C − B
= −1 + 8 − 2
∴ Dy = 5
Hence, the fourth vertex is (7, 5).
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