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प्रश्न
Find the 10th term of the A.P. –40, –15, 10, 35,...
योग
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उत्तर
In this problem, we are given different A.P. and we need to find the required term of that A.P.
10th term of the A.P. −40, −15, 10, 35,...
Here
First term (a) = -40
Common difference of the A.P (d) = -15 - (-40)
= -15 + 40
= 25
Now as we know
`a_n = a + (n - 1)d`
So for 10th term
`a_10 = a + (10 - 1)d`
= -40 + (9)25
= -40 + 225
= 185
Therefore the 10th term of the given A.P is `a_10 = 185`
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क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Arithmetic Progressions - EXERCISE 5.4 [पृष्ठ ५.१८]
