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प्रश्न
Find ten rational numbers between \[\frac{1}{4} \text{and} \frac{1}{2} .\]
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उत्तर
\[\text{The L . C . M of the denominators (2 and 4) is 4 .} \]
\[\text{So, we can write} \frac{1}{4} \text{as it is .} \]
\[\text{Also,} \frac{1}{2} = \frac{1 \times 2}{2 \times 2} = \frac{2}{4}\]
\[\text{As the integers between the numerators 1 and 2 of both the fractions are not sufficient, we will multiply the fractions by 20 .} \]
\[ \therefore \frac{1}{4} = \frac{1 \times 20}{4 \times 20} = \frac{20}{80}\]
\[\frac{2}{4} = \frac{2 \times 20}{4 \times 20} = \frac{40}{80}\]
\[\text{Between 20 and 40, there are 19 integers . They are 21, 22, 23, 24, 25, 26, 27 . . . . 39, 40 . }\]
\[\text{Thus,} \frac{21}{40}, \frac{22}{40}, \frac{23}{40}, \frac{24}{40}, \frac{25}{40}, . . . . . . . . . . . . . . . . . . . \frac{38}{40} and \frac{39}{40} are the fractions . \]
\[\text{We can take any 10 of these .} \]
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The average life expectancies of males for several states are shown in the table. Express each decimal in the form `p/q` and arrange the states from the least to the greatest male life expectancy. State-wise data are included below; more indicators can be found in the “FACTFILE” section on the homepage for each state.
| State | Male | `bb(p/q)` form | Lowest terms |
| Andhra Pradesh | 61.6 | ||
| Assam | 57.1 | ||
| Bihar | 60.7 | ||
| Gujarat | 61.9 | ||
| Haryana | 64.1 | ||
| Himachal Pradesh | 65.1 | ||
| Karnataka | 62.4 | ||
| Kerala | 70.6 | ||
| Madhya Pradesh | 56.5 | ||
| Maharashtra | 64.5 | ||
| Orissa | 57.6 | ||
| Punjab | 66.9 | ||
| Rajasthan | 59.8 | ||
| Tamil Nadu | 63.7 | ||
| Uttar Pradesh | 58.9 | ||
| West Bengal | 62.8 | ||
| India | 60.8 |
Source: Registrar General of India (2003) SRS Based Abridged Lefe Tables. SRS Analytical Studies, Report No. 3 of 2003, New Delhi: Registrar General of India. The data are for the 1995-99 period; states subsequently divided are therefore included in their pre-partition states (Chhatisgarh in MP, Uttaranchal in UP and Jharkhand in Bihar)
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