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प्रश्न
Find the slope of a line parallel tp PQ, if the coordinates of P and Q are (11,-3) and (7,13) respectively.
योग
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उत्तर
Slope of line PQ = `("y"_2 - "y"_1)/("x"_2 - "x"_1)`
= `(13 + 3)/(7 - 11) = - 16/(-4)`
= -4
Slope of line parallel to PQ
= Slope of PQ
= -4
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