Question

Find the sine ratio of θ in standard position whose terminal arm passes through (3, 4)

Answer 1

Terminal arm passes through (3, 4).

\[\therefore r = \sqrt{x^2 + y^2} = \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5\]

Hence, 

\[\sin\theta = \frac{y}{r} = \frac{4}{5}\]