Advertisements
Advertisements
प्रश्न
Find the remainder when x3 + 3x2 + 3x + 1 is divided by x + π.
Advertisements
उत्तर १
Let p(x) = x3 + 3x2 + 3x + 1
x + π = 0 ⇒ x = -π
∴ Remainder = (-π)3 + 3(-π)2 - 3(-π) + 1
= -π3 + 3π2 - 3π + 1
Therefore, the remainder is -π3 + 3π2 - 3π + 1.
उत्तर २
By long division,
Therefore, the remainder is -π3 + 3π2 - 3π + 1.
संबंधित प्रश्न
Using remainder theorem, find the value of m if the polynomial f(x)= x3 + 5x2 -mx +6 leaves a remainder 2m when divided by (x-1),
A polynomial f(x) when divided by (x - 1) leaves a remainder 3 and when divided by (x - 2) leaves a remainder of 1. Show that when its divided by (x - i)(x - 2), the remainder is (-2x + 5).
Find the remainder when the polynomial f(x) = 2x4 - 6x3 + 2x2 - x + 2 is divided by x + 2.
Using remainder theorem, find the remainder on dividing f(x) by (x + 3) where f(x) = 2x2 – 5x + 1
Find ‘a’ if the two polynomials ax3 + 3x2 – 9 and 2x3 + 4x + a, leaves the same remainder when divided by x + 3.
If on dividing 4x2 – 3kx + 5 by x + 2, the remainder is – 3 then the value of k is
By Remainder Theorem find the remainder, when p(x) is divided by g(x), where p(x) = x3 – 2x2 – 4x – 1, g(x) = x + 1
By Remainder Theorem find the remainder, when p(x) is divided by g(x), where p(x) = 4x3 – 12x2 + 14x – 3, g(x) = 2x – 1
A polynomial in ‘x’ is divided by (x – a) and for (x – a) to be a factor of this polynomial, the remainder should be ______.
4x2 – kx + 5 leaves a remainder 2 when divided by x – 1. The value of k is ______.
