Question

Find the length of the diagonal of a square whose area is `128 cm^2` Also, find its perimeter.  

Answer 1

Area of the square= `128 cm^2` 

Area =` 1/2 d^2` (where d is a diagonal of the square)  

⇒` 128=1/2 d^2` 

⇒` d^2=256` 

⇒`d=16 cm` 

Now,

`Area= "Side^2"`  

⇒` 128= "side"^2` 

⇒`" Side"= 11.31 cm` 

Perimeter= `4` (side) 

=`4(11.31)`

=`45.24 cm`