Question

Find the length of a chord which is at a distance of 5 cm from the centre of a circle ofradius 10 cm.

Answer 1

Given that
Distance (OC)=5cm
Radius of circle (OA)10cm
In OCA by Pythagoras theorem

`AC^2+OC^2=OA^2`

`⇒AC^2+5^2=10^2`

`⇒AC=sqrt75=8.66cm`

WRK, the perpendicular from center to chord bisects the chord

`∴AC=BC=8.66cm` 

Then chord AB=8.66+8.66

= 17.32 cm