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प्रश्न
Find the integerating factor of the differential equation `xdy/dx - 2y = 2x^2` .
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उत्तर
`dy/dx + (-2/x)y = 2x`
compare with `dy/dx + py = Q`
⇒ `p = -2/x`
`therefore` Integrating factor `IF = e^(∫pdx)`
= `e^(∫-2/xdx)`
= `e^(-2"In "x)`
= `e^("In" x^-2)`
= `x^-2`
= `1/x^2`
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