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प्रश्न
Find if the following number is a perfect cube?
1728
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उत्तर
1728
| 2 | 1728 |
| 2 | 864 |
| 2 | 432 |
| 2 | 216 |
| 2 | 108 |
| 2 | 54 |
| 3 | 27 |
| 3 | 9 |
| 3 | 3 |
| 1 |
∵ 1728 = 2 x 2 x 2 x 2 x 2 x 2 x 3 x 3 x 3
= (2)3 x (2)3 x (3)3
∵ 1728 is a perfect cube.
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Square root of a number x is denoted by `sqrt(x)`.
