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प्रश्न
Find the following product:
0.1y(0.1x5 + 0.1y)
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उत्तर
To find the product, we will use distributive law as follows:
\[0 . 1y\left( 0 . 1 x^5 + 0 . 1y \right)\]
\[ = \left( 0 . 1y \right)\left( 0 . 1 x^5 \right) + \left( 0 . 1y \right)\left( 0 . 1y \right)\]
\[ = \left( 0 . 1 \times 0 . 1 \right)\left( y \times x^5 \right) + \left( 0 . 1 \times 0 . 1 \right)\left( y \times y \right)\]
\[ = \left( 0 . 1 \times 0 . 1 \right)\left( x^5 \times y \right) + \left( 0 . 1 \times 0 . 1 \right)\left( y^{1 + 1} \right)\]
\[ = 0 . 01 x^5 y + 0 . 01 y^2\]
Thus, the answer is \[0 . 01 x^5 y + 0 . 01 y^2\].
संबंधित प्रश्न
Express each of the following product as a monomials and verify the result in each case for x = 1:
(4x2) × (−3x) × \[\left( \frac{4}{5} x^3 \right)\]
Evaluate (−8x2y6) × (−20xy) for x = 2.5 and y = 1.
Evaluate each of the following when x = 2, y = −1.
\[\left( \frac{3}{5} x^2 y \right) \times \left( - \frac{15}{4}x y^2 \right) \times \left( \frac{7}{9} x^2 y^2 \right)\]
Find the product 24x2 (1 − 2x) and evaluate its value for x = 3.
Multiply \[- \frac{3}{2} x^2 y^3 by (2x - y)\] and verify the answer for x = 1 and y = 2.
Simplify: 2x2(x3 − x) − 3x(x4 + 2x) − 2(x4 − 3x2)
Multiply:
(x2 + y2) by (3a + 2b)
Multiply:
(0.8a − 0.5b) by (1.5a − 3b)
Multiply:
23xy2 × 4yz2
What is the product of 3x and 4x²?
