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प्रश्न
Find the equation of the plane passing through the point (2, 4, 6) and making equal intercepts on the coordinate axes.
योग
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उत्तर
We know that the equation of the plane whose intercepts on the coordinate axes area, bandcis
`x/a + y/b + z/c` = 1
Given that the plane makes equal intercepts on the coordinate axes
So, a = b = c
So, the equation of the plane is
`x/a + y/a + z/a` = 1
x + y + z = a ...(1)
This plane passes through the point (2, 4, 6).
Substituting this point in (1), we get
2 + 4 + 6 = a
a = 12
Substituting this in (1), we get
x + y + z = 12
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