Question

Find the cube of \[\frac{7}{9}\] .

 

Answer 1

\[\because\] \[\left( \frac{m}{n} \right)^3 = \frac{m^3}{n^3}\]

\[\therefore\] \[\left( \frac{7}{9} \right)^3 = \frac{7^3}{9^3} = \frac{7 \times 7 \times 7}{9 \times 9 \times 9} = \frac{343}{729}\]