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प्रश्न
Find the components along the coordinate axes of the position vector of the following point :
Q(–5, 1)
योग
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उत्तर
The position vector of point Q(-5,1), \[\overrightarrow{OQ} = - 5 \hat{i} + \hat{j}\] Component of \[\overrightarrow{OQ}\] along x-axis = a vector of magnitude 5 having its direction along the negative direction of x-axis.
Component of \[\overrightarrow{OQ}\] along y axis = a vector of magnitude 1 having its direction along the positive direction of y-axis.
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