Advertisements
Advertisements
प्रश्न
Find the area of the region bounded by the curves y = x2 + 2, y = x, x = 0 and x = 3
Advertisements
उत्तर
The area bounded by the curves, y = x2 + 2, y = x, x = 0, and x = 3, is represented by the shaded area OCBAO as
Then, Area OCBAO = Area ODBAO – Area ODCO
APPEARS IN
संबंधित प्रश्न
Find the area of the circle 4x2 + 4y2 = 9 which is interior to the parabola x2 = 4y
Using integration find the area of the triangular region whose sides have the equations y = 2x +1, y = 3x + 1 and x = 4.
Smaller area enclosed by the circle x2 + y2 = 4 and the line x + y = 2 is
A. 2 (π – 2)
B. π – 2
C. 2π – 1
D. 2 (π + 2)
Using the method of integration find the area bounded by the curve |x| + |y| = 1 .
[Hint: The required region is bounded by lines x + y = 1, x– y = 1, – x + y = 1 and
– x – y = 1].
Choose the correct answer The area of the circle x2 + y2 = 16 exterior to the parabola y2 = 6x is
A. `4/3 (4pi - sqrt3)`
B. `4/3 (4pi + sqrt3)`
C. `4/3 (8pi - sqrt3)`
D.`4/3 (4pi + sqrt3)`
Show that the rectangle of the maximum perimeter which can be inscribed in the circle of radius 10 cm is a square of side `10sqrt2` cm.
Find the area included between the parabolas y2 = 4ax and x2 = 4by.
The area enclosed between the curves y = loge (x + e), x = loge \[\left( \frac{1}{y} \right)\] and the x-axis is _______ .
Area lying between the curves y2 = 4x and y = 2x is
Solve the following :
Find the area of the region lying between the parabolas y2 = 4x and x2 = 4y.
The area enclosed between the two parabolas y2 = 20x and y = 2x is ______ sq.units
Find the area of the ellipse `x^2/1 + y^2/4` = 1, in first quadrant
Find the area of sector bounded by the circle x2 + y2 = 25, in the first quadrant−
Find the area enclosed between the X-axis and the curve y = sin x for values of x between 0 to 2π
Find the area of the ellipse `x^2/36 + y^2/64` = 1, using integration
Find the area of the region included between the parabola y = `(3x^2)/4` and the line 3x – 2y + 12 = 0.
Find the area of the region bounded by the curves x = at2 and y = 2at between the ordinate corresponding to t = 1 and t = 2.
Calcualte the area under the curve y = `2sqrt(x)` included between the lines x = 0 and x = 1
Draw a rough sketch of the curve y = `sqrt(x - 1)` in the interval [1, 5]. Find the area under the curve and between the lines x = 1 and x = 5.
Determine the area under the curve y = `sqrt("a"^2 - x^2)` included between the lines x = 0 and x = a.
Area lying between the curves `y^2 = 4x` and `y = 2x`
Let the area enclosed by the x-axis, and the tangent and normal drawn to the curve 4x3 – 3xy2 + 6x2 – 5xy – 8y2 + 9x + 14 = 0 at the point (–2, 3) be A. Then 8A is equal to ______.
Using Integration, find the area of triangle whose vertices are (– 1, 1), (0, 5) and (3, 2).
Find the area enclosed between 3y = x2, X-axis and x = 2 to x = 3.
