Advertisements
Advertisements
प्रश्न
Find the amount of Rs 4096 for 18 months at
Advertisements
उत्तर
Given:
P = Rs 4, 096
R = 12 . 5 % p . a .
n = 18 months = 1 . 5 years
We have:
\[\text{ A = P }\left( 1 + \frac{R}{100} \right)^n \]
When the interest is compounded semi - annually, we have:
\[\text{ A = P }\left( 1 + \frac{R}{200} \right)^{2n} \]
\[ =\text{ Rs }4, 096 \left( 1 + \frac{12 . 5}{200} \right)^3 \]
\[ =\text{ Rs }4, 096 \left( 1 . 0625 \right)^3 \]
\[ =\text{ Rs }4, 913\]
Thus, the required amount is Rs 4, 913.
APPEARS IN
संबंधित प्रश्न
Fabina borrows Rs 12,500 at 12% per annum for 3 years at simple interest and Radha borrows the same amount for the same time period at 10% per annum, compounded annually. Who pays more interest and by how much?
Swati took a loan of Rs 16000 against her insurance policy at the rate of \[12\frac{1}{2} %\] per annum. Calculate the total compound interest payable by Swati after 3 years.
Roma borrowed Rs 64000 from a bank for \[1\frac{1}{2}\] years at the rate of 10% per annum. Compute the total compound interest payable by Roma after \[1\frac{1}{2}\] years, if the interest is compounded half-yearly.
Find the compound interest on Rs 64000 for 1 year at the rate of 10% per annum compounded quarterly.
Find the amount of Rs 2400 after 3 years, when the interest is compounded annually at the rate of 20% per annum.
Abha purchased a house from Avas Parishad on credit. If the cost of the house is Rs 64000 and the rate of interest is 5% per annum compounded half-yearly, find the interest paid by Abha after one year and a half.
Find the rate at which a sum of money will double itself in 3 years, if the interest is compounded annually.
Amount when interest is compounded annually is given by the formula ______.
If amount on the principal of Rs 6,000 is written as `6000 [1 + 5/100]^3` and compound interest payable half yearly, then rate of interest p.a. is ______ and time in years is ______.
The compound interest on a sum of Rs P for T years at R% per annum compounded annually is given by the formula `P(1 + R/100)`.
