Advertisements
Advertisements
प्रश्न
Find the compound interest at the rate of 10% per annum for two years on that principal which in two years at the rate of 10% per annum gives Rs 200 as simple interest.
Advertisements
उत्तर
SI \[= \frac{PRT}{100}\]
\[ \therefore P = \frac{SI \times 100}{RT}\]
\[ = \frac{200 \times 100}{10 \times 2}\]
= Rs 1, 000
A = P \[\left( 1 + \frac{R}{100} \right)^n \]
\[ = 1, 000 \left( 1 + \frac{10}{100} \right)^2 \]
\[ = 1, 000 \left( 1 . 10 \right)^2 \]
= Rs 1, 210
Now,
CI = A - P
= Rs 1, 210 - Rs 1, 000
= Rs 210
APPEARS IN
संबंधित प्रश्न
Find the amount and the compound interest on Rs 10,000 for `1 1/2` years at 10% per annum, compounded half yearly. Would this interest be more than the interest he would get if it was compounded annually?
Find the compound interest when principal = Rs 3000, rate = 5% per annum and time = 2 years.
Mewa Lal borrowed Rs 20000 from his friend Rooplal at 18% per annum simple interest. He lent it to Rampal at the same rate but compounded annually. Find his gain after 2 years.
Ramesh deposited Rs 7500 in a bank which pays him 12% interest per annum compounded quarterly. What is the amount which he receives after 9 months.
Find the amount of Rs 12500 for 2 years compounded annually, the rate of interest being 15% for the first year and 16% for the second year.
Find the rate percent per annum if Rs 2000 amount to Rs 2662 in \[1\frac{1}{2}\] years, interest being compounded half-yearly?
A sum of money deposited at 2% per annum compounded annually becomes Rs 10404 at the end of 2 years. Find the sum deposited.
The compound interest on a sum of Rs P for T years at R% per annum compounded annually is given by the formula `P(1 + R/100)`.
If principal = Rs 1,00,000. rate of interest = 10% compounded half yearly. Find amount after 6 months.
If principal = Rs 1,00,000. rate of interest = 10% compounded half yearly. Find interest for next 6 months.
