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प्रश्न
Factorise the following:
x(x + 2y – z) – 2yz
योग
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उत्तर
Given: x(x + 2y – z) – 2yz
Step-wise calculation:
1. Expand the first term:
x(x + 2y – z) = x2 + 2xy – xz
2. Substitute back:
x2 + 2xy – xz – 2yz
3. Group terms to factor by grouping:
x2 + 2xy – (xz + 2yz)
4. Factor out common terms in the grouped parts:
From the first two terms:
x(x + 2y)
From the last two terms:
–z(x + 2y)
5. Take out the common factor (x + 2y):
(x + 2y)(x – z)
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