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प्रश्न
Factorise the following:
x3 – 3x2 – 2x + 6
योग
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उत्तर
Given expression: x3 – 3x2 – 2x + 6
Step-wise calculation:
1. Group the terms:
(x3 – 3x2) + (–2x + 6) ]
2. Factor each group:
x2(x – 3) – 2(x – 3)
3. Take the common factor (x – 3):
(x – 3)(x2 – 2)
4. Recognize (x2 – 2) can be written as `(x - sqrt(2))(x + sqrt(2))` if further factorization over the reals is considered.
x3 – 3x2 – 2x + 6 = (x – 3)(x2 – 2)
or fully factored over the reals,
= `(x - 3)(x - sqrt(2))(x + sqrt(2))`
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