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Factorise the following: x^2 – x(3a + 2b) + 6ab - Mathematics

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प्रश्न

Factorise the following:

x2 – x(3a + 2b) + 6ab

योग
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उत्तर

Given expression: x2 – x(3a + 2b) + 6ab

Step-wise calculation:

Step 1: Expand the middle term:

x2 – 3ax – 2bx + 6ab

Step 2: Rewrite the expression grouping terms to factor by grouping:

x2 – 3ax – 2bx + 6ab = x2 – 3ax – 2bx + 6ab

Step 3: Group terms:

(x2 – 3ax) – (2bx – 6ab)

Step 4: Factor out common factors from each group:

x(x – 3a) – 2b(x – 3a)

Step 5: Factor out the common binomial factor:

(x – 3a)(x – 2b)

So, the factorization of the given expression is (x – 3a)(x – 2b).

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अध्याय 4: Factorisation - Exercise 4B [पृष्ठ ८०]

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नूतन Mathematics [English] Class 9 ICSE
अध्याय 4 Factorisation
Exercise 4B | Q 11. | पृष्ठ ८०
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