Advertisements
Advertisements
प्रश्न
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
a2x2 + 2abx + b2
योग
Advertisements
उत्तर
We have,
a2x2 + 2abx + b2
= (ax)2 + 2 × ax × b + b2
= (ax + b)2
= (ax + b)(ax + b)
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Algebraic Expression, Identities and Factorisation - Exercise [पृष्ठ २३४]
APPEARS IN
संबंधित प्रश्न
Find the following squares by suing the identities.
(6x2 − 5y)2
Using a2 − b2 = (a + b) (a − b), find 512 − 492
Expand (ax + by)2
Use an expansion formula to find the value.
(997)2
Use the formula to multiply the following.
(a + 6) (a − 6)
Expand the following square, using suitable identities
(mn + 3p)2
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
4x2 + 4x + 1
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
2x3 + 24x2 + 72x
The area of a square is 9x2 + 24xy + 16y2. Find the side of the square.
Factorise p4 + q4 + p2q2.
