Advertisements
Advertisements
प्रश्न
Factorise the following by the difference of two squares:
x2 + y2 - z2 - 2xy
योग
Advertisements
उत्तर
x2 + y2 - z2 - 2xy
= x2 + y2 - 2xy - z2
= (x2 + y2 - 2xy) - z2
= (x - y)2 - (z)2
= (x - y - z)(x - y + z).
shaalaa.com
Method of Factorisation : Difference of Two Squares
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Factorise : a3 + 2a2 - a - 2
Factorise : 9a2 + 3a - 8b - 64b2
Factorise : 4x2 - 12ax - y2 - z2 - 2yz + 9a2
Factorise:
(a2 − 1) (b2 − 1) + 4ab
Factorise : `4x^2 + 1/(4x)^2 + 1`
Factorise the following by the difference of two squares:
625 - b2
Factorise the following by the difference of two squares:
`"m"^2 - (1)/(9)"n"^2`
Factorise the following by the difference of two squares:
16a4 - 81b4
Factorise the following:
9(a - b)2 - (a + b)2
Express each of the following as the difference of two squares:
(x2 - 2x + 3)(x2 + 2x + 3)
