Advertisements
Advertisements
प्रश्न
Factorise the following by the difference of two squares:
`"m"^2 - (1)/(9)"n"^2`
योग
Advertisements
उत्तर
`"m"^2 - (1)/(9)"n"^2`
= `"m"^2 - (1/3"n")^2`
=`("m" - 1/3"n")("m" + 1/3"n")`.
shaalaa.com
Method of Factorisation : Difference of Two Squares
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Factorise : a2 - 81 (b-c)2
Factorise : a4 - 1
Factorise : 4a2 - 49b2 + 2a - 7b
Factorise : 4xy - x2 - 4y2 + z2
Factorise : 4x2 - 12ax - y2 - z2 - 2yz + 9a2
Factorise : `4x^2 + 1/(4x)^2 + 1`
Factorise : a2 ( b + c) - (b + c)3
Factorise the following by the difference of two squares:
441 - 81y2
Factorise the following:
`x^2 + (1)/x^2 - 2`
Express each of the following as the difference of two squares:
(x2 - 2x + 3)(x2 + 2x + 3)
