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प्रश्न
Factorise the following by the difference of two squares:
64x2 - 121y2
योग
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उत्तर
64x2 - 121y2
= (8x)2 - (1y)2
= (8x - 11y)(8x + 11y).
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Method of Factorisation : Difference of Two Squares
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