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प्रश्न
Factorise the following:
b(x – y) – 3(y – x) + a(y – x)
योग
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उत्तर
b · (x – y) – 3(y – x) + a · (y – x)
Factor out the negative sign from the expression and reorder the terms:
b · (x – y) – 3 · (– (x – y)) + a · (y – x)
Factor out the negative sign from the expression and reorder the terms:
b · (x – y) – 3 · (– (x – y)) + a · (– (x – y))
Multiplying two negatives equals a positive: (–) · (–) = (+)
b · (x – y) + 3(x – y) + a · (– (x – y))
Multiplying a positive and a negative equals a negative: (+) · (–) = (–)
b · (x – y) + 3(x – y) – a · (x – y)
Factor out x – y from the expression:
(x – y) · (b + 3 – a)
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