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प्रश्न
Factorise the following:
(ax – by)2 – (bx – ay)2
योग
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उत्तर
Given expression: (ax – by)2 – (bx – ay)2
Step-wise calculation
Step 1: Recognize this as a difference of squares:
A2 – B2 = (A + B)(A – B), where A = (ax – by), B = (bx – ay)
Step 2: Apply the formula:
(ax – by)2 – (bx – ay)2
= ((ax – by) + (bx – ay)) × ((ax – by) – (bx – ay))
Step 3: Simplify each factor:
(ax – by) + (bx – ay)
= ax – by + bx – ay
= (ax – ay) + (bx – by)
= a(x – y) + b(x – y)
= (a + b)(x – y)
(ax – by) – (bx – ay)
= ax – by – bx + ay
= (ax – bx) + (ay – by)
= x(a – b) + y(a – b)
= (a – b)(x + y)
Step 4: Therefore,
(ax – by)2 – (bx – ay)2
= (a + b)(x – y) × (a – b)(x + y)
Step 5: Rearranging the factors:
(a + b)(a – b)(x – y)(x + y)
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