Advertisements
Advertisements
प्रश्न
Factorise the following:
(a2 - 2a)2 - 23(a2 - 2a) + 120
Advertisements
उत्तर
(a2 - 2a)2 - 23(a2 - 2a) + 120
= (a2 - 2a)2 - 15(a2 - 2a) - 8(a2 - 2a) + 120
= (a2 - 2a)(a2 - 2a - 15) - 8(a2 - 2a - 15)
= (a2 - 2a - 15)(a2 - 2a - 8)
= (a2 - 5a + 3a - 15)(a2 - 4a + 2a - 8)
= [a(a - 5) + 3(a - 5)][a(a - 4) + 2(a - 4)]
= [(a - 5)(a + 3)][(a - 4)(a + 2)]
= (a - 5)(a + 3)(a - 4)(a + 2)
= (a + 2)(a + 3)(a - 4)(a - 5).
APPEARS IN
संबंधित प्रश्न
Factorise : a2 - 3a - 40
Factorise:
a(3a - 2) - 1
Factorise : x2 + 3x + 2 + ax + 2a
Factorise the following by splitting the middle term:
x2 + 5x - 6
Factorise the following by splitting the middle term:
p2- 12p - 64
Factorise the following by splitting the middle term:
y2 - 2y - 24
Factorise the following:
5x2 - 17xy + 6y2
Factorise the following:
2x3 + 5x2y - 12xy2
Factorise the following:
12(2x - 3y)2 - 2x + 3y - 1
Factorise: 2x2 + 5x - 18
