Advertisements
Advertisements
प्रश्न
Factorise the following:
(a2 – b2)(c2 – d2) – 4abcd
Advertisements
उत्तर
(a2 – b2)(c2 – d2) – 4abcd
= a2c2 – a2d2 – b2c2 + b2d2 – 4abcd
= a2c2 + b2d2 – 2abcd – a2d2 – b2c2 – 2abcd
= (a2c2 + b2d2 – 2abcd) – (a2d2 + b2c2 + 2abcd)
= (ac – bd)2 – (ad + bc)2
= [(ac – bd) + (ad + bc)][(ac – bd) – (ad + bc)]
= (ac – bd + ad + bc)(ac – bd – ad – bc).
संबंधित प्रश्न
Factorise : a2 + b2 - c2 - d2 + 2ab - 2cd
Factorise : (a2 + b2 - 4c2)2 - 4a2b2
Factorise : 4x4 - x2 - 12x - 36
Factorise the following by the difference of two squares:
x2 - 16
Factorise the following by the difference of two squares:
64x2 - 121y2
Factorise the following by the difference of two squares:
x6 - 196
Factorise the following by the difference of two squares:
`"m"^2 - (1)/(9)"n"^2`
Factorise the following by the difference of two squares:
16a4 - 81b4
Factorise the following:
25(x - y)2 - 49(c - d)2
Factorise the following:
y4 + y2 + 1
