Advertisements
Advertisements
प्रश्न
Factorise the following:
(a2 – b2)(c2 – d2) – 4abcd
Advertisements
उत्तर
(a2 – b2)(c2 – d2) – 4abcd
= a2c2 – a2d2 – b2c2 + b2d2 – 4abcd
= a2c2 + b2d2 – 2abcd – a2d2 – b2c2 – 2abcd
= (a2c2 + b2d2 – 2abcd) – (a2d2 + b2c2 + 2abcd)
= (ac – bd)2 – (ad + bc)2
= [(ac – bd) + (ad + bc)][(ac – bd) – (ad + bc)]
= (ac – bd + ad + bc)(ac – bd – ad – bc).
APPEARS IN
संबंधित प्रश्न
Factorise : a4 - 1
Factorise: 4a2 - (4b2 + 4bc + c2)
Factorise : a2 + b2 - c2 - d2 + 2ab - 2cd
Factorise : x4 + x2 + 1
Factorise the following by the difference of two squares:
441 - 81y2
Factorise the following by the difference of two squares:
x6 - 196
Factorise the following:
(x2 + y2 – z2)2 – 4x2y2
Factorise the following:
a2 + b2 – c2 – d2 + 2ab – 2cd
Factorise the following:
y4 + y2 + 1
Express each of the following as the difference of two squares:
(x2 - 2x + 3) (x2 - 2x - 3)
