Advertisements
Advertisements
प्रश्न
Factorise the following:
5 - 4(a - b) - 12(a - b)2
योग
Advertisements
उत्तर
5 - 4(a - b) - 12(a - b)2
= 5 - 10(a - b) + 6(a - b) - 12(a - b)2
= 5[1 - 2(a - b)] + 6(a - b)[1 - 2(a - b)]
= [5 + 6(a - b)][1 - 2(a - b)]
= (5 + 6a - 6b)(1 - 2a + 2b).
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Factorise.
p2 − 2p − 35
Factorise:
(2a + b)2 - 6a - 3b - 4
Factorise : x2 + 3x + 2 + ax + 2a
Factorise : (3x - 2y)2 + 3 (3x - 2y) - 10
Factorise the following by splitting the middle term:
3x2 + 19x - 14
Factorise the following:
5x2 - 17xy + 6y2
Factorise the following:
y2 + 3y + 2 + by + 2b
Factorise the following:
`6sqrt(3)x^2 - 19x + 5sqrt(3)`
Factorise the following:
(a2 - 2a)2 - 23(a2 - 2a) + 120
Factorise the following:
12 - (y + y2)(8 - y - y2)
