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प्रश्न
Factorise the following:
4x2 - 12ax - y2 - z2 - 2yz + 9a2
योग
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उत्तर
4x2 - 12ax - y2 - z2 - 2yz + 9a2
= (4x2 - 12ax + 9a2) - (y2 + z2 + 2yz)
= (2x - 3a)2 - (y + z)2
= [(2x - 3a) + (y + z)][(2x - 3a) - (y + z)]
= (2x - 3a + y + z)(2x - 3a - y - z).
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Method of Factorisation : Difference of Two Squares
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