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प्रश्न
Factorise the following:
4x2 – a2 + 2a – 1
योग
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उत्तर
Given expression: 4x2 – a2 + 2a – 1
Step-wise calculation:
1. Rearrange and group the terms:
4x2 – (a2 – 2a + 1)
2. Recognize the terms inside the parentheses as a perfect square:
a2 – 2a + 1 = (a – 1)2
3. Substitute to get a difference of squares:
4x2 – (a – 1)2
4. Use the identity A2 – B2 = (A – B)(A + B), where A = 2x, B = (a – 1)
5. So: 4x2 – (a – 1)2 = (2x – (a – 1))(2x + (a – 1))
6. Simplify the factors: (2x – a + 1)(2x + a – 1)
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