Advertisements
Advertisements
प्रश्न
Factorise the following:
2a2 + 9a + 10
Advertisements
उत्तर
Product = 2 × 10 = 20, sum = 9
Split the middle term as 5a and 4a
2a2 + 9a + 10 = 2a2 + 5a + 4a + 10
= a(2a + 5) + 2(2a + 5)
= (2a+ 5)(a+ 2)
APPEARS IN
संबंधित प्रश्न
Write the coefficient of x2 in the following:
`pi/6x^2- 3x+4`
Write the degrees of the following polynomials
0
Verify whether the indicated numbers is zeros of the polynomials corresponding to them in the following case:
\[p(x) = x^3 - 6 x^2 + 11x - 6, x = 1, 2, 3\]
If the polynomials 2x3 + ax2 + 3x − 5 and x3 + x2 − 4x +a leave the same remainder when divided by x −2, find the value of a.
Find the value k if x − 3 is a factor of k2x3 − kx2 + 3kx − k.
2y3 − 5y2 − 19y + 42
If x2 + x + 1 is a factor of the polynomial 3x3 + 8x2 + 8x + 3 + 5k, then the value of k is
Factorise the following:
a2 + 10a – 600
Factorise the following:
`1/x^2 + 1/y^2 + 2/(xy)`
If x + 2a is a factor of x5 – 4a2x3 + 2x + 2a + 3, find a.
