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प्रश्न
Factorise the following:
121x2 – 169y2
योग
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उत्तर
The given expression is,
121x2 – 169y2
Here we use the identity
a2 – b2 = (a + b)(a – b)
Taking a = 11x and b = 13y, we get
∴ 121x2 – 169y2
= (11x)2 – (13y)2
= (11x – 13y)(11x + 13y)
Therefore, the factors of the given expression are (11x – 13y)(11x + 13y)
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