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प्रश्न
Factorise the following:
1 – 18a – 63a2
योग
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उत्तर
Given expression: 1 – 18a – 63a2
We have to find two numbers whose sum is –18 and whose product is –63.
These numbers are –21 and 3.
Now, using middle term factorisation method,
1 – 18a – 63a2
= 1 – 21a + 3a – 63a2
= (1 – 21a + 3a) (1 – 21a)
= (1 – 21a)(1 + 3a)
The factorisation result is (1 – 21a) (1 + 3a).
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