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Factorise the following: 1 – 18a – 63a2 - Mathematics

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प्रश्न

Factorise the following:

1 – 18a – 63a2

योग
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उत्तर

Given expression: 1 – 18a – 63a2

We have to find two numbers whose sum is –18 and whose product is –63. 

These numbers are –21 and 3.

Now, using middle term factorisation method,

1 – 18a – 63a2

= 1 – 21a + 3a – 63a2

= (1 – 21a + 3a) (1 – 21a)

= (1 – 21a)(1 + 3a)

The factorisation result is (1 – 21a) (1 + 3a).

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अध्याय 4: Factorisation - EXERCISE 4C [पृष्ठ ४४]

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बी निर्मला शास्त्री Mathematics [English] Class 9 ICSE
अध्याय 4 Factorisation
EXERCISE 4C | Q I. 3. | पृष्ठ ४४
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