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प्रश्न
Factorise : a4 - 1
योग
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उत्तर
a4 - 1
= ( a2 )2 - ( 1 )2
= ( a2 + 1 )( a2 - 1 ) [ ∵ a2 - b2 = ( a + b )( a - b )]
= ( a2 + 1 )[ (a)2 - (1)2 ]
= ( a2 + 1 )( a + 1 )( a - 1 )
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Method of Factorisation : Difference of Two Squares
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