Advertisements
Advertisements
प्रश्न
Factorise : 4a2b - 9b3
योग
Advertisements
उत्तर
4a2b - 9b3
= b( 4a2 - 9b2 )
= b[ (2a)2 - (3b)2 ]
= b( 2a - 3b )( 2a + 3b ) [ ∵ a2 - b2 = ( a + b )( a - b )]
shaalaa.com
Method of Factorisation : Difference of Two Squares
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Factorise : a2 - 81 (b-c)2
Factorise:
9(a − 2)2 − 16(a + 2)2
Factorise : 4a2 - 12a + 9 - 49b2
Factorise : 4x2 - 12ax - y2 - z2 - 2yz + 9a2
Factorise:
(a2 − 1) (b2 − 1) + 4ab
Factorise : (x2 + 4y2 - 9z2)2 - 16x2y2
Factorise : (a + b) 2 - a2 + b2
Factorise : `4x^2 + 1/(4x)^2 + 1`
Factorise the following by the difference of two squares:
`"m"^2 - (1)/(9)"n"^2`
Factorise the following:
y4 + y2 + 1
