Advertisements
Advertisements
प्रश्न
Factorise : 1 - 2a - 2b - 3 (a + b)2
योग
Advertisements
उत्तर
1 - 2a - 2b - 3 (a + b)2
1 - 2(a + b) - 3(a + b)2
Let a + b = x
= 1 - 2x - 3x2
= -3x2 - 2x + 1
= - [3x2 + 2x - 1]
= - [3x2 + (3 - 1)x - 1]
= - [3x2 + 3x - 1x - 1]
= - [3x + (x + 1) - 1(x + 1]
= - (x + 1) (3x - 1)
= (x + 1) (1 - 3x)
= (a + b + 1) [1 - 3(a + b)]
= (a + b + 1) (1 - 3a - 3b)
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Factorise.
p2 − 2p − 35
Factorise.
m2 − 23m + 120
Factorise.
44x2 − x − 3
Factories: (x2 - 3x)(x2 - 3x - 1) - 20.
Factorise the following by splitting the middle term:
7x2 + 40x - 12
Factorise the following:
9x2 - 22xy + 8y2
Factorise the following:
2x3 + 5x2y - 12xy2
Factorise the following:
5(3x + y)2 + 6(3x + y) - 8
Factorise the following:
(t2 - t)(4t2 - 4t - 5) - 6
Factorise the following:
2a3 + 5a2b - 12ab2
