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प्रश्न
Express the following as a product of powers of their prime factors:
9000
सारिणी
योग
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उत्तर
| 2 | 9000 |
| 2 | 4500 |
| 2 | 2250 |
| 3 | 1125 |
| 3 | 375 |
| 5 | 125 |
| 5 | 25 |
| 5 | 5 |
| 1 |
Using prime factorisation of 9000, we have
9000 = 2 × 2 × 2 × 3 × 3 × 5 × 5 × 5
∴ 9000 = 22 × 32 × 53
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संबंधित प्रश्न
Find the value of 112.
Simplify:
72 × 22
Compare the following numbers:
2.7 × 1012; 1.5 × 108
Compare the following numbers:
4 × 1014; 3 × 1017
Evaluate:
`[(-3/4)^-2]^2`
Evaluate: `((- 3)/(- 5))^3`
Which is greater:
54 or 45
Find the value of `(4/5)^3`.
432 = 24 × 3—
Express the following in exponential form:
a × a × b × b × b × c × c × c × c
