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Express sin 67° + cos 75° in terms of trigonometric ratios of angles between 0° and 45° - Mathematics

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प्रश्न

Express sin 67° + cos 75° in terms of trigonometric ratios of angles between 0° and 45°

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उत्तर

∵ 23 = 90 – 67 & 15 = 90 – 75

∴ sin 67° + cos 75°

= sin (90 – 23)° + cos (90 – 15)°

= cos 23° + sin 15°.

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अध्याय 8: Introduction to Trigonometry - Exercise 8.3 [पृष्ठ १९०]

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एनसीईआरटी Mathematics [English] Class 10
अध्याय 8 Introduction to Trigonometry
Exercise 8.3 | Q 7 | पृष्ठ १९०
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