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प्रश्न
Explain VSEPR theory. Applying this theory to predict the shapes of IF7 and SF6.
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उत्तर
Lewis’s concept of the structure of molecules deals with the relative position of atoms in the molecules and sharing of electron pairs between them. However, we cannot predict the shape of the molecule using Lewis concept. Lewis theory in combination with VSEPR theory will be useful in predicting the shape of molecules.
IF7:
Iodine has 7 valence electrons in the valence shell. In an excited state it has 6 valency electrons by 1st and 2nd excited state & under sp3d2, hybridization and combines with 7 Fluorine to get pentagonal bipyramidal shape. There are no lone pairs.
I = ns2 np5 nd0
pentagonal bipyramidal
SF6:
Sulphar attain six valence electron in 1st and 2nd excited states undergoes sp3d2 hybridization and combines with six ‘F’ atoms, as there no lone pair electrons it geometry in octahedral.
S = 16 = ns2 np4 nd0
Octahedral
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संबंधित प्रश्न
Discuss the shape of the following molecules using the VSEPR model:
BeCl2, BCl3, SiCl4, AsF5, H2S, PH3
Shape of ClF3 is ______.
Select the INCORRECT match.
Identify the molecule with linear geometry?
Explain the non-linear shape of \[\ce{H2S}\] and non-planar shape of \[\ce{PCl3}\] using valence shell electron pair repulsion theory.
Elements \[\ce{X, Y}\] and \[\ce{Z}\] have 4, 5 and 7 valence electrons respectively. Write the molecular formula of the compounds formed by these elements individually with hydrogen.
Number of lone pair(s) of electrons on central atom and the shape of BrF3 molecule respectively are ______.
The number of lone pairs of electrons on the central I atom in `"I"_3^-` is ______.
In the following structure, the percentage of the 's' character in the lone pair occupy by the oxygen atom is ______.
Given: Cos θ = −0.99
What is the number of lone pair of electrons in IF7?
