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प्रश्न
Explain the release of energy in nuclear fission and fusion on the basis of binding energy per nucleon curve.
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उत्तर
The binding energy of each nucleon and a portion of its mass are transformed and released as energy during the fusion process. When heavier nuclei split apart into lighter nuclei, energy is also released in the fission process. The desire of an atomic nucleus to become more stable is what drives fission and fusion. Thus, the most stable nuclei will have a mass number of about 60, which explains why iron is the most stable element in the universe.
- The fusion of lighter-than-iron elements could release energy to create nuclei with higher binding energy (per nucleon).
- The energy released during the fission of elements heavier than iron may lead to the creation of nuclei with higher binding energies (per nucleon).
Particularly when merging tiny nuclei like hydrogen and helium into larger nuclei, nuclear fusion produces more energy than nuclear fission.
संबंधित प्रश्न
Is the nucleus formed in the decay of the nucleus `""_11^22Na`, an isotope or isobar?
The neutron separation energy is defined as the energy required to remove a neutron from the nucleus. Obtain the neutron separation energies of the nuclei `""_20^41"Ca"` and `""_13^27 "Al"` from the following data:
`"m"(""_20^40"Ca")` = 39.962591 u
`"m"(""_20^41"Ca")` = 40.962278 u
`"m"(""_13^26"Al")` = 25.986895 u
`"m"(""_13^27"Al")` = 26.981541 u
Use this graph to explain the release of energy in both the processes of nuclear fusion and fission.
In which of the following decays the atomic number decreases?
(a) α-decay
(b) β+-decay
(c) β−-decay
(d) γ-decay
The figure shows the plot of binding energy (BE) per nucleon as a function of mass number A. The letters A, B, C, D, and E represent the positions of typical nuclei on the curve. Point out, giving reasons, the two processes (in terms of A, B, C, D, and E ), one of which can occur due to nuclear fission and the other due to nuclear fusion.
Calculate the binding energy of an alpha particle given its mass to be 4.00151 u.
An electron in hydrogen atom stays in its second orbit for 10−8 s. How many revolutions will it make around the nucleus at that time?
Determine the binding energy per nucleon of the americium isotope \[\ce{_95^244Am}\], given the mass of \[\ce{_95^244Am}\] to be 244.06428 u.
Nuclei with magic no. of proton Z = 2, 8, 20, 28, 50, 52 and magic no. of neutrons N = 2, 8, 20, 28, 50, 82 and 126 are found to be very stable.
(i) Verify this by calculating the proton separation energy Sp for 120Sn (Z = 50) and 121Sb = (Z = 51).
The proton separation energy for a nuclide is the minimum energy required to separate the least tightly bound proton from a nucleus of that nuclide. It is given by `S_P = (M_(z-1^' N) + M_H - M_(ZN))c^2`.
Given 119In = 118.9058u, 120Sn = 119.902199u, 121Sb = 120.903824u, 1H = 1.0078252u.
(ii) What does the existance of magic number indicate?
Which of the following quantities is a measure of stability of nucleus?
