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प्रश्न
Explain the octet rule for the formation of –
Sodium chloride from a sodium atom and a chlorine atom.
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उत्तर
Formation of sodium chloride NaCl, Na atom has atomic number 11 [2, 8, 1], There is 1 electron in the outermost M shell it is not possible to gain 7 electrons and to lose 1 electron is easier, by losing sodium atom because of \[\ce{Na+}\] ion.
While Cl atomic number 17 [2, 8, 7] has 7 electrons in outermost M shell for Cl atom it is easier to gain 1 electron, becomes \[\ce{Cl-}\] ion.
By losing 1 electron and by gaining 1 electron both sodium and chlorine attain octet configuration and become stable and there is the electrostatic force that pulls them and becomes sodium chloride.

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संबंधित प्रश्न
Summarize the rules for writing of distribution of electrons in various shells for the first eighteen elements.
What is the maximum number of electrons an M shell of the atom can accommodate?
What is the maximum number of electrons which can be accommodated in the :
(a) innermost shell of an atom?
(b) outermost shell of an atom?
What is the Electronic Configuration of a Hydrogen Atom?
What are ‘energy levels’?
Differentiate between the term Duplet and octet rule.
The following element is given \[\ce{_3U}\]. State the electronic configuration and state whether it is a metal, non-metal, or inert gas.
The following element is given \[\ce{_6V}\]. State the electronic configuration and state whether it is a metal, non-metal, or inert gas.
State true or false. If false, correct the statement.
The maximum number of electron in L Shell is 10.
The outermost shell of an atom cannot accommodate electrons more than ______.
