Advertisements
Advertisements
प्रश्न
Explain Reflection at curved surfaces.
Advertisements
उत्तर
- When the sound waves are reflected from the curved surfaces, the intensity of the reflected waves is changed.
- When reflected from a convex surface, the reflected waves are diverged out and the intensity is decreased.
- When sound is reflected from a concave surface, the reflected waves are converged and focused at a point. So the intensity of reflected waves is concentrated at a point.
- Parabolic surfaces are used when it is required to focus the sound at a particular point. Hence, many halls are designed with parabolic reflecting surfaces.
- In elliptical surfaces, sound from one focus will always be reflected the other focus, no matter where it strikes the wall.
APPEARS IN
संबंधित प्रश्न
A wire of length 80 cm has a frequency of 256 Hz. Calculate the length of a similar wire under similar tension, which will have frequency 1024 Hz
Define amplitude term in relation to a wave.
State two differences between the light and sound waves.
What is the condition necessary for an echo to be heard distinctly?
Name the waves which are used in sonar to find the depth of a sea. Give one reason for their use.
What is a bulb horn ? Name the principle on which a bulb horn works.
Draw a labelled diagram to show the multiple reflections of sound in a part of the stethoscope tube.
Point out the waves from the given list, i.e., light, sound, radio waves, ultrasonic waves, and thermal radiation, the energy is propagated by mechanical waves.
How are bats able to fly in the dark?
What do you understand by the ‘Echolocation system of Dolphins’?
State two factors on which the natural frequency of a body depends.
When a sound is made from a distance of 18 m, in front of a tall building, it is found to get repeated again. Which phenomenon is associated with this observation? Give a brief explanation of this phenomenon?
Draw a diagram representing a wave of amplitude 4 cm and wavelength 2 m. If the frequency of the wave is 150 Hz, calculate its velocity.
A sound wavelength of 0.332 m has a time period of 10−3 s. If the time period is decreased to 10−4 s, calculate the wavelength and frequency of the new wave.
