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प्रश्न
Explain how soaked seeds swell up and burst their seed coats.
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उत्तर
When soaked in water, the seeds swell up due to imbibition and endosmosis. During these two processes water enters the cell. Due to endosmosis, at some point, the seed coat is unable to bear the turgor pressure and hence, the seed coat bursts.
संबंधित प्रश्न
Differentiate between Turgor pressure and Wall pressure (explain)
Complete the following statements:
Hypotonic solution is one in which the solution kept outside the cell has lower solute concentration than ……………… the cell.
The diagram given below represents an experimental set-up to demonstrate a certain process. Study the same and answer the questions that follow:
- Name the process.
- Define the above-named process.
- What would you observe in the experimental set-up after an hour or so?
- What control experiment can be set up for comparison?
- Keeping in mind the root hair, cell and its surroundings, name the parts that correspond to
- concentrated sugar solution
- parchment paper
- water in the beaker
- Name any other material that can be used instead of parchment paper in the above experiment.
- Mention two advantages of the process for the plants.
Show by a series of diagrams, the change which a plant cell will undergo when placed in
Hypotonic salt solution
Define the following:
Diffusion
Two potato cubes each 1 cm3 in size, were placed separately in two containers (A and B), the container A having water and the other (B) containing concentrated sugar solution. After 24 hours when the cubes were examined, those placed in water were found to be firm and had increased slightly in size and those placed in concentrated sugar solution were found to be soft and somewhat decreased in size. Use the above information to answer the questions that follow:
Account for the softness and decrease in size of the potato cubes which were placed in sugar solution.
What is the water potential?
In the figure below ‘A’ shows a cell in the normal state and ‘B’ shows the same cell after leaving it in a certain solution for a few minutes.
(i) Describe the change which has occurred in the cell as seen in B.
(ii) Give the technical term for the condition of the cell as reached in B and as it was in A.
(iii) Define the process which led to this condition.
(iv) What was the solution-isotonic, hypotonic or hypertonic, in which the cell was kept?
(v) How can the cell in B, be brought back to its original condition?
(vi) Name the parts numbered 1 to 3.
Give Technical Term for the following.
Solutions which have the same osmotic pressure.
Give Technical Term for the following.
A solution whose concentration is equal to the cell sap.
