Advertisements
Advertisements
प्रश्न
Explain the fact that why organic com pounds are Iarge in number.
Advertisements
उत्तर
Organic compounds are large in number due to the following unique properties of carbon atom:
a) Tetra covalency of carbon : Carbon has four alence shell electrons. Thus it always forms covalent bonds by sharing electrons with other atoms.
b) Catenation : it is the property of combining any number of carbon atoms to form straight chains, branched chains and rings of different sizes.
c) Formation of multiple bonds: due to small size carbon atom can form multiple bonds with not only carbon but with atoms of other elements like oxyzen, nitrogen etc.
d) isomerism : It forms large number of compounds due to isomerism by means of which compounds having same molecular formula can be have different structural formula.
APPEARS IN
संबंधित प्रश्न
Name an organic compound which is used for illuminating country houses.
Give the various applications of organic chemistry?
Draw the chain isomers of hexane (C6H14).
Give the reactions of ethyne with Water.
What type of reaction is common to both of these compounds?
Give the correct IUPAC name and the fiJnctional group for each of the
compounds whose structural formulae are given below:
\[\begin{array}{cc}
\phantom{......}\ce{H}\phantom{..}\ce{H}\phantom{..}\ce{H}\phantom{........}\\
\phantom{}|\phantom{...}|\phantom{...}|\phantom{..}\\
\ce{H-C-C-C-OH}\\
\phantom{}|\phantom{...}|\phantom{...}|\phantom{..}\\
\phantom{......}\ce{H}\phantom{..}\ce{H}\phantom{..}\ce{H}\phantom{........}\\
\end{array}\]
Define isomerism.
Write the equation for the reaction taking place between 1, 2-dibromoethane and alcoholic potassium hydroxide.
Draw the structural formula for the following :
propanoic acid
Give the IUPAC name of the organic compound represented by the structural formula given below:
\[\begin{array}{cc}
\phantom{.}\ce{H\phantom{...}H\phantom{...}O}\phantom{..}\\
\phantom{.}|\phantom{....}|\phantom{....}||\phantom{..}\\
\ce{H - C - C - C - OH}\\
\phantom{}|\phantom{....}|\phantom{......}\\
\phantom{}\ce{H\phantom{...}H}\phantom{......}
\end{array}\]
