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प्रश्न
Expand the following:
`(3x - 1/(2x))^2`
योग
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उत्तर
Given: `(3x - 1/(2x))^2`
Step-wise calculation:
We use the identity (a – b)2 = a2 – 2ab + b2 where a = 3x and `b = 1/(2x)`.
1. Square the first term:
(3x)2 = 9x2
2. Square the second term:
`(1/(2x))^2 = 1/(4x^2)`
3. Calculate twice the product of the two terms:
`2 xx (3x) xx 1/(2x) = 2 xx 3x xx 1/(2x)`
`2 xx (3x) xx 1/(2x) = 3`
Putting it all together:
`(3x - 1/(2x))^2 = 9x^2 - 3 + 1/(4x^2)`
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